printf() & scanf() : Common Mistakes!

Let's remember this situation - our whole code is okay, but when I want to take input (in Codeblocks), our codes stop running and returns an error.

Let's remember another situation - we added a = 10 with b = 20 and stored in c = a + b. So output must be 30. But when we run our code,

we see that the output is a 6 digit number or it gives 0!

Do they still happen in your life? Then this section is for you.

Syntax of scanf() function

- scanf("%DataType", &VariableName);

    - If you mistakenly forget to put the ampersand(&) sign before the variable, your code will crash and will terminate instantly.

    If you face this sort of problem that your code is not taking input then do not panic and check all the scanf() functions.

    

    - But if you are scanning a string, you must not use ampersand(&)!

Syntax of printf() function

- printf("%DataType", VariableName);

    - If you mistakenly use an ampersand(&) sign before the variable name, your code will print a 6 digit number which indicates the memory position of the variable. This happens frequently when we copy a scanf() line and change the scanf to printf but forget to remove the ampersand(&) signs. So, if this happens, do not panic and check all the printf() functions.

    

    - If you mistakenly use wrong datatype, your program may give a output 0 or anything can happen. But in most cases, I found 0. You can write a code and run it to see the changes. But if this sort of things happen, check all printf() functions.

You may try to write some codes using these mistakes and see what happens. I would highly suggest you to do so. Because, if we do not make mistakes, we can never learn.

Let's try this yourself - What happens when you use a wrong datatype in a scanf() function?

Happy Coding!